Readers ,our today topic isProgression(series)
First of all
Progression is nothing but series, in which numbers are arranged in some pattern.
Progression has 3 types
1)Arithmetic Progression
2)Geometric Progression
3)Harmonic Progression
Define :
If Difference of any two consecutive number in the series is called Arithmetic Progression
Series is a,a+d,a+2d,......a+(n-1)d
a=first term in the series
d=difference of consecutive number
Ex.2,5,8,11.....
Formulas:
->If we want to find nth term in this progression , formula is tn=a+(n-1)d
here
tn=nth term in the series
a=first term in the series
d=difference of consecutive number
->If we want to find the Summation of all number of series, then formula is
Sn=n/2[2a+(n-1)d]
where,
Sn=Summation Of all number in the series
a=first term in the series
d=difference of consecutive number
n=total member in the series
->If we know the first term and last term in this series then Summation Formula is easy
that is Sn=n(a+l)/2
where,
Sn=Summation Of all number in the series
a=first term in the series
l=last number in the series
n=total member in the series
Define :
If ratio of any two consecutive number in the series is called Arithmetic Progression
Series is a, a*r, a(r^2), a(r^3),a(r^4),a(r^5).....,a(r^n)
a=first term in the series
r=ratio of two consecutive number
Formulas:
->If we want to find nth term in this progression , formula is tn=a*(r^ n-1)
here
tn=nth term in the series
a=first term in the series
r=ratio of two consecutive number
->If we want to find the Summation of all number of series, then formula is
Sn=a(1- r^n)/(1-r) if r<1
Sn=a(r^n -1 )/(r-1) if r>1
where,
Sn=Summation Of all number in the series
a=first term in the series
r=ratio of two consecutive number
n=total member(number) in the series
->In this series if infinite number is available
then Summation is
Sn=a/(1-r) where -1<r<1
Define :
If numbers' reciprocal is in the Arithmetic Progression, then series of number is called Harmonic Progression
Series is 1/a , 1/(a+d) , 1/(a+2d) , 1/(a+3d),........
Formulas:
->To find the nth term of this series
you should find nth term of corresponding arithmetic progression and then reciprocal of that.
if series is 1/2 , 1/4 , 1/6 .... then
to find n th term first we find nth term of 2,4,6....
then reciprocal of it is nth term of Harmonic Progression.
I hope this post will help to understand the topic of Progression
Our next topic will be on Median
thank U.
First of all
Progression is nothing but series, in which numbers are arranged in some pattern.
Progression has 3 types
1)Arithmetic Progression
2)Geometric Progression
3)Harmonic Progression
We start with Arithmetic Progression
Define :
If Difference of any two consecutive number in the series is called Arithmetic Progression
Series is a,a+d,a+2d,......a+(n-1)d
a=first term in the series
d=difference of consecutive number
Ex.2,5,8,11.....
Formulas:
->If we want to find nth term in this progression , formula is tn=a+(n-1)d
here
tn=nth term in the series
a=first term in the series
d=difference of consecutive number
->If we want to find the Summation of all number of series, then formula is
Sn=n/2[2a+(n-1)d]
where,
Sn=Summation Of all number in the series
a=first term in the series
d=difference of consecutive number
n=total member in the series
->If we know the first term and last term in this series then Summation Formula is easy
that is Sn=n(a+l)/2
where,
Sn=Summation Of all number in the series
a=first term in the series
l=last number in the series
n=total member in the series
Geometric Progression
Define :
If ratio of any two consecutive number in the series is called Arithmetic Progression
Series is a, a*r, a(r^2), a(r^3),a(r^4),a(r^5).....,a(r^n)
a=first term in the series
r=ratio of two consecutive number
Formulas:
->If we want to find nth term in this progression , formula is tn=a*(r^ n-1)
here
tn=nth term in the series
a=first term in the series
r=ratio of two consecutive number
->If we want to find the Summation of all number of series, then formula is
Sn=a(1- r^n)/(1-r) if r<1
Sn=a(r^n -1 )/(r-1) if r>1
where,
Sn=Summation Of all number in the series
a=first term in the series
r=ratio of two consecutive number
n=total member(number) in the series
->In this series if infinite number is available
then Summation is
Sn=a/(1-r) where -1<r<1
Harmonic Progression
If numbers' reciprocal is in the Arithmetic Progression, then series of number is called Harmonic Progression
Series is 1/a , 1/(a+d) , 1/(a+2d) , 1/(a+3d),........
Formulas:
->To find the nth term of this series
you should find nth term of corresponding arithmetic progression and then reciprocal of that.
if series is 1/2 , 1/4 , 1/6 .... then
to find n th term first we find nth term of 2,4,6....
then reciprocal of it is nth term of Harmonic Progression.
I hope this post will help to understand the topic of Progression
Our next topic will be on Median
thank U.
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