Quantitative Aptitude
1) 3.6+36.6+3.66+.36+3.0=?
a)44.22 b)77.22
c)74.22 d)47.22 e) none of these
Sol>It is just simple addition of given numbers , and answer will be 47.22
2) 23*45 / 15 =?
a)69 b)65
c)63 d)71 e)none of these
Sol> 23*45 / 15
=1035 / 15
= 69
3) 4(5/6)+7(1/2)-5(8/11)
a)2(10/33) b)6(20/33)
c)2(20/33) d)6(10/33) e)none of these
Sol> 4(5/6) + 7(1/2) - 5(8/11)
= (29/6) + (15/2) - (63/11)
=(319 + 495 - 378) / 66
=(436) / 66
=218/33
=6(20/33)
4) (210/14) * (17/15) * ? =4046
a)202 b)218
c)233 d)227 e)none of these
Sol> suppose unknown term is x
so (210/14) * (17/15) * x = 4046
=> x=(4046 * 14 *15 ) / (210 * 17)
=> x=238
So ans will be None Of These
5) 83% of 2350= ?
a)1509.5 b)1950.5
c)1905.5 d)1590.5 e)none of these
Sol> 83% of 2350
=2350 * (83/100)
= 195050/100
=1950.5
So ans will be 1950.5
6) √1089 +3 = (?)^2
a)5 b)6
c)3 d)8 e)4
Sol>Suppose unknown value is x
so √1089 +3 = (x)^2
=>33 + 3 = (x)^2
=> 36 = (x)^2
=> √36 = x
=> 6=x
so x= 6 is the answer
7) 96+32*5-31 = ?
a)223 b)225
c)229 d)221 e)none of these
Sol>
Suppose unknown value is x
96+32*5-31 = x
=> 96 + 160 - 31 =x
=>96 + 129 =x
=>x= 225
8) ? / 36 =(7)^2 - 8
a)1426 b)1449
c)1463 d)1476 e)none of these
Sol>
Suppose unknown value is x
x / 36 =(7)^2 - 8
=> x / 36 =49 - 8
=> x/36 = 41
=> x=41*36
=>x=1476
9)√8281 = ?
a)89 b)97
c)93 d)91 e)83
Sol>
Suppose unknown value is x
so √8281 = x
=> √13*13*7*7 =x
=> 13* 7 =x
=> x= 91
10) (63)^2 - (12)^2 =?
a) 3528 b)3852
c)3582 d)3825 e)none of these
Sol>
Suppose unknown value is x
(63)^2 - (12)^2 =x
=> 3969 - 144 =x
=> x= 3825
11) 1(4/5) + 3(3/5) = ? - 4(3/10)
a) 9 (7/10) b)7(7/10)
c)9(3/10) d)7(9/10) e)none of these
Sol>
Suppose unknown value is x
1(4/5) + 3(3/5) = x - 4(3/10)
=> (9/5) + (18/5) = x - (43/10)
=> (9+18) / 5 = x - (43/10)
=> 27/5 = x - (43/10)
=> (27/5) + (43/10) = x
=> (54 + 43) / 10 =x
=> 97/10 =x
=> x= 9 (7/10)
12)17 * 19 *4 / ? =161.5
a)8 b)6
c)7 d)9 e)none of these
sol>
Suppose unknown value is x
17 * 19 *4 / x =161.5
=> 1292 / x =161.5
=> 1292 / 161.5 =x
=> x=8
13) 1798 / 31 * ? =348
a)3 b)6
c)4 d)5 e)none of these
Sol>
Suppose unknown value is x
so 1798 / 31 * x =348
=> 58 * x=348
=> x= 348/58
=> x=6
14) (9.8 * 2.3 + 4.46 ) / 3 =(3) ^ ?
a)3 b)9
c)5 d)2 e)none of these
Sol>
Suppose unknown value is x
so (9.8 * 2.3 + 4.46 ) / 3 =(3) ^ x
=> (27) / 3 =(3) ^ x
=> 9 =(3) ^ x
=>(3)^2 =(3) ^ x
=> so x=2
15) 43% of 600 + (?)% of 300 =399
a)45 b)41
c)42 d)47 e)none of these
Sol>
Suppose unknown value is x
so 43% of 600 + (x)% of 300 =399
=> 600* (43 /100 ) + 300 * (x/100) =399
=> 258 + 3x = 399
=> 3x = 141
=> x = 47
16)What will be the compound interest on a sum of Rs.7500/- at 4 p.c.p.a in 2 years?
a) 618/- b)612/-
c)624/- d)606/- e)621/-
Sol>
A=P+I where A=Amount, P= Principal Amount , I =Compound Interest
and A=P(1 + R/100)^N
=>I= A - P
=>I=P(1 + R/100)^N - P
=>I=7500(1+ 4/100)^2 - 7500
=>I=7500(1+0.04)^2 - 7500
=>I=7500(1.04)^2 -7500
=>I=8112 - 7500
=>I=612
a) 618/- b)612/-
c)624/- d)606/- e)621/-
Sol>
A=P+I where A=Amount, P= Principal Amount , I =Compound Interest
and A=P(1 + R/100)^N
=>I= A - P
=>I=P(1 + R/100)^N - P
=>I=7500(1+ 4/100)^2 - 7500
=>I=7500(1+0.04)^2 - 7500
=>I=7500(1.04)^2 -7500
=>I=8112 - 7500
=>I=612
So Compound Interest IS Rs. 612/-
17)In how many different ways can the letters of the word 'CREAM' can be arranged?
a)720 b)240
c)360 d)504 e) e)none of these
Sol>
CREAM has 5 letters in word,
So different ways for arranged are = 5P5 =5! =5*4*3*2*1 =120
18)The Circumference of a circle is 792 meters.What will be its radius?
a)120 meters b)133meters
c)145meters d) 136meters e)none of these
Sol> Circumference of circle is = 2 ∏ r , where r=radius of the circle
=>792 = 2 ∏ r
=>792 = 2*(22/7)*r
=> r=(792*7)/(22*2)
=>r =126 meters.
19)Cost of 36 pens and 42 pencils is Rs 460/- ,what is the cost of 18 pens and 21 pencils?
a)Rs 230/- b)Rs 203/-
c)Rs 302/- d)Rs320/- e)none of these
Sol> Suppose x is for pen and y is for pencils
then Cost of 36 pens and 42 pencils is Rs 460/-
=> 36x + 42y =460
=>2(18x + 21y) =460
=> 18x + 21 y =460/2 =230 - - - - - - (1)
Now the cost of 18 pens and 21 pencils?
=>18x+21y=?
From (1) Ans is Rs 230/-
20)The ratio of ages of A and B seven years ago was 3:4 respectively.The ratio of their ages nine years from now will be 7:8 respectively. What is the B's age at present?
a)16 years b)19 years
c)28 years d)23 years e)none of these
Sol>
Suppose Today age of A is x years and age of B is y years
before 7 years (From today)
=>A's Age is (x-7)years and B's Age is (y-7)years and ratio of their ages 3:4
=> (x-7)/(y-7) = 3/4
=> 4x - 28 =3y - 21
=> 4x-3y=7 - - - - - (1)
Now after 9 years (From today)
=> A's Age is (x+9)years and B's Age is (y+9)years and ratio of their ages 7:8
=>(x+9) / (y+9) = 7/8
=> 8x + 72 = 7y +63
=> 8x - 7y = -9 - - - - (2)
Now from equation (1) and equation (2) solving
4x - 3y =7 - - - - - x2
8x-7y= -9
8x-6y=14
8x-7y= -9
------------------
- + +
------------------
y=23 years
where y is B's Age at present so it is the answer
21) In how many years will Rs.4600 amount to Rs.5428 at 3 p.c.p.a simple interest?
a)3 b)5
c)6 d)4 e)none of these
Sol>
Formula for interest is
I=PRN /100 ,where P=Principal Amount , R=Rate Of Simple Interest, N=years
I =simple interest
and A=P+I , where A=Amount
here, A= Rs.5428 , P=Rs.4600
So, I=A-P=5428-4600=828
Now I=PRN /100
=>828 = (4600 * 3 * N ) /100
=>828*100 / 4600 *3 = N
=> N=6 years
22)What will be the average of the following set of scores?
59,84,44,98,30,40,58
a)62 b)66
c)75 d)52 e)59
Sol> Average =Sum of all n numbers/ n , here n=7
=>Average=(59+84+44+98+30+40+58)/7
=>Average=413/7
=> Average=59
23) The sum of three consecutive odd numbers is 1383.what is the largest number?
a)463 b)459
c)457 d)461 e)none of these
Sol>
Suppose three consecutive odd numbers are x-2,x,x+2
Their sums are 1383
so x-2+x+x+2=1383
=>3x=1383
=>x=461
Numbers are x-2=459 , x=461 , x+2=463
So the largest number is 463
24-26 Study the information given below and answer the questions that follow:
An article was bought for Rs.5600. Its price was marked up by 12%. Thereafter it was sold at a discount of 5% on the marked price.
24)what was the marked price of the article?
a)Rs 6207 b)Rs.6242
c)Rs.6292 d)Rs.6192 e)Rs.6272
Sol> article marking up by 12%,
so the marked price is = 5600 + 12% of 5600
= 5600 + ( 5600*12/100 )
=5600 +672
=6272
So the answer is Rs.6272
25)What was the percent profit on the transaction?
a)6.8% b)6.3%
c)6.4% d)6.6% e)6.2%
Sol>
here the marked price is Rs.6272 from above solution
Now 5% discount given on marked price
so new price is=marked price - (5% of marked price)
=6272 - (5% of 6272)
=6272 - (6272 * 5/100)
=6272 - (313.6)
=5958.4
So profit (in %)=(gain / cost price )*100
=(358.4/5600 )* 100 , because gain=5958.4 - 5600=258.4
=6.4%
26)What was the amount of discount given?
a)Rs.319.6 b)Rs.303.6
c)RS.306.3 d)RS.313.6 e)Rs.316.9
Sol> discount = 5% of marked price
= 5% of 6272
= 313.6
discount=Rs 313.6
17)In how many different ways can the letters of the word 'CREAM' can be arranged?
a)720 b)240
c)360 d)504 e) e)none of these
Sol>
CREAM has 5 letters in word,
So different ways for arranged are = 5P5 =5! =5*4*3*2*1 =120
18)The Circumference of a circle is 792 meters.What will be its radius?
a)120 meters b)133meters
c)145meters d) 136meters e)none of these
Sol> Circumference of circle is = 2 ∏ r , where r=radius of the circle
=>792 = 2 ∏ r
=>792 = 2*(22/7)*r
=> r=(792*7)/(22*2)
=>r =126 meters.
19)Cost of 36 pens and 42 pencils is Rs 460/- ,what is the cost of 18 pens and 21 pencils?
a)Rs 230/- b)Rs 203/-
c)Rs 302/- d)Rs320/- e)none of these
Sol> Suppose x is for pen and y is for pencils
then Cost of 36 pens and 42 pencils is Rs 460/-
=> 36x + 42y =460
=>2(18x + 21y) =460
=> 18x + 21 y =460/2 =230 - - - - - - (1)
Now the cost of 18 pens and 21 pencils?
=>18x+21y=?
From (1) Ans is Rs 230/-
20)The ratio of ages of A and B seven years ago was 3:4 respectively.The ratio of their ages nine years from now will be 7:8 respectively. What is the B's age at present?
a)16 years b)19 years
c)28 years d)23 years e)none of these
Sol>
Suppose Today age of A is x years and age of B is y years
before 7 years (From today)
=>A's Age is (x-7)years and B's Age is (y-7)years and ratio of their ages 3:4
=> (x-7)/(y-7) = 3/4
=> 4x - 28 =3y - 21
=> 4x-3y=7 - - - - - (1)
Now after 9 years (From today)
=> A's Age is (x+9)years and B's Age is (y+9)years and ratio of their ages 7:8
=>(x+9) / (y+9) = 7/8
=> 8x + 72 = 7y +63
=> 8x - 7y = -9 - - - - (2)
Now from equation (1) and equation (2) solving
4x - 3y =7 - - - - - x2
8x-7y= -9
8x-6y=14
8x-7y= -9
------------------
- + +
------------------
y=23 years
where y is B's Age at present so it is the answer
21) In how many years will Rs.4600 amount to Rs.5428 at 3 p.c.p.a simple interest?
a)3 b)5
c)6 d)4 e)none of these
Sol>
Formula for interest is
I=PRN /100 ,where P=Principal Amount , R=Rate Of Simple Interest, N=years
I =simple interest
and A=P+I , where A=Amount
here, A= Rs.5428 , P=Rs.4600
So, I=A-P=5428-4600=828
Now I=PRN /100
=>828 = (4600 * 3 * N ) /100
=>828*100 / 4600 *3 = N
=> N=6 years
22)What will be the average of the following set of scores?
59,84,44,98,30,40,58
a)62 b)66
c)75 d)52 e)59
Sol> Average =Sum of all n numbers/ n , here n=7
=>Average=(59+84+44+98+30+40+58)/7
=>Average=413/7
=> Average=59
23) The sum of three consecutive odd numbers is 1383.what is the largest number?
a)463 b)459
c)457 d)461 e)none of these
Sol>
Suppose three consecutive odd numbers are x-2,x,x+2
Their sums are 1383
so x-2+x+x+2=1383
=>3x=1383
=>x=461
Numbers are x-2=459 , x=461 , x+2=463
So the largest number is 463
24-26 Study the information given below and answer the questions that follow:
An article was bought for Rs.5600. Its price was marked up by 12%. Thereafter it was sold at a discount of 5% on the marked price.
24)what was the marked price of the article?
a)Rs 6207 b)Rs.6242
c)Rs.6292 d)Rs.6192 e)Rs.6272
Sol> article marking up by 12%,
so the marked price is = 5600 + 12% of 5600
= 5600 + ( 5600*12/100 )
=5600 +672
=6272
So the answer is Rs.6272
25)What was the percent profit on the transaction?
a)6.8% b)6.3%
c)6.4% d)6.6% e)6.2%
Sol>
here the marked price is Rs.6272 from above solution
Now 5% discount given on marked price
so new price is=marked price - (5% of marked price)
=6272 - (5% of 6272)
=6272 - (6272 * 5/100)
=6272 - (313.6)
=5958.4
So profit (in %)=(gain / cost price )*100
=(358.4/5600 )* 100 , because gain=5958.4 - 5600=258.4
=6.4%
26)What was the amount of discount given?
a)Rs.319.6 b)Rs.303.6
c)RS.306.3 d)RS.313.6 e)Rs.316.9
Sol> discount = 5% of marked price
= 5% of 6272
= 313.6
discount=Rs 313.6
27)The area of the rectangle is 1209 square meters. Its length measures 39 meters.How much is its perimeter?
a)122 meter b)134 meter
c)148 meter d)144 meter e)none of these
Sol> Area of rectangle=length * width
here length=39 meter , area=1209 square meters
so 1209 =39 * width
=>width= 1209/39
=>width=31 meter
Now Perimeter of rectangle= 2 (length + width)
=2(39+31)
=2(70)
=140meter
So ans is none of these
a)122 meter b)134 meter
c)148 meter d)144 meter e)none of these
Sol> Area of rectangle=length * width
here length=39 meter , area=1209 square meters
so 1209 =39 * width
=>width= 1209/39
=>width=31 meter
Now Perimeter of rectangle= 2 (length + width)
=2(39+31)
=2(70)
=140meter
So ans is none of these
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