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(2^1096 + 2^2248 + 2^2n) find the value of n so that the value will be perfect square

(a)2011 (b)2012 (c)2010 (d)2008

Answer with ur approach...

sol>

 

2 series is 2,4,6,8.................then 2^1096 give last digit 6......2^2248 gives last digit 6 then............................................................................... now through option if 2^4022 then last digit8.................if 2^4024 then last digit 6........if 2^4020 then last digit 6 and for 2^4016 then last digit 6................................................................................ then trying to sum with all 3 numbers =sum of their last digit 6+6+8 is only number give last digit 0..................................which may be perfect square..............................................................................and for other case 6+6+6=last digit 8 will never perfect square..............thats why 2011 is the ans